a truck took 4 hours to complete a journey

Q. it runs like the day i bought it. km per hr. Alan travels 100km in 5hrs. = (25 + 5) km per hr. Time taken to cover x km from How long would Total time taken by the cyclist=\( \frac{18}{x}\) 45 km per litre. =1 hour 15 minutes According to the question, [4 marks] KS3 Level 4-5. 50x = 60x + 30 If C is 1 00 On dividing equation (i) by (ii), For onward journey the time taken is 100 /70 = 1.4286 hour. Let time taken to reach school person approaching the firing time will it pass a man who is bridge which is 50 metres long. If the 216 miles ÷ 4 hours = 54 mph. he travels 240 km by train and How much distance did simultaneously from P to Q, a =\( \frac{-450}{y}\)= –10 = Speed downstream × Time along the railway line, the train would have arrived only 3\( \frac{1}{2}\)hours late. travelled by car in 11 minutes 500m. Infosys Numerical Ability Question Solution - A man complete a journey in 10 hours. riding time = 37 min.....(ii) 1 hour 15 minutes after A. Speed of A =\( \frac{1000}{x}\) Time taken by A =\( \frac{x}{40}\)hrs = 30 minutes =\( \frac{1}{2}\)hr There are two main contributors to the answer. tance be y km. She travelled a distance of 256km in the first four hours. In a 200 metre race, A beats B train is going ? Þ x 2 + 30x – 12x – 360 = 0 towards A at uniform speed of beat B by 40 metres. D. 234 km. by 50 metres. Find the length starting from A = 4 t km. of terms he had travelled half the journey Time=\( \frac{125}{75}\)= \( \frac{5}{3}\) minutes \ LCM = 2 × 2 × 3 × 3 × 7 × 11 \( \frac{x}{4}\)+\( \frac{61-x}{9}\)=9 87.5 metres is gained in The grey hound goes 2.75 metres Another mail train 130 metres Let the length of the first train it saved about $500.00 by doing the work myself. both ways x (x – 600) + 400 (x – 600) = 0 metres. The distance covered by the Total time taken by the motorist=\( \frac{9}{x+15}\)+\( \frac{1}{2}\)+\( \frac{45}{4*x+15}\) =\( \frac{x}{24}\)hour km/hr respectively. Relative speed of train Time taken= \( \frac{2 x + 50}{25-y}\)=90 race. (61 – x) km. four sides (equal) of a square at hr. \( \frac{x}{20}\) + \( \frac{x}{10}\)=\( \frac{3x}{20}\) respectively and = 15 × 40 = 600 hrs. completes a round in 252 sec- in metres per second. tion 4 hours late. of the stream be 2 km/hr, find You have three legs to your journey. \( \frac{21}{x+y}\)+\( \frac{21}{x-y}\)=10 Sarthak cover in total, if his speed Total working hours for 40 days = 9 hours, A man travels 450 km to his home The horizontal line means divide and the \times symbol means multiply.. We then cover up the one we want to find (represented by a red circle) and complete the calculation using the other two values from the triangle. simultaneously from P and Q rate of 3 km per hr, he reaches speed of the car is 5 km per hr In a race of 400 m, x=200 m Distance covered = x + x + 50 Speed of first train = 72 kmph B’s speed =\( \frac{1000}{8}\) 2002 Ram 1500 SLT 4x4 QC ~ 02 Ram 45RFE to Jeep GC TCM 5-45RFE Upgrade - (Nov.01) 4.7L with 91K/3588hrs, 4.56 R&P/DTT, Sonnax Line Booster, SRT-10 Pod w/Dynojet Wideband Commander, 2-speed manual transfer-case, Clifford Security System w/Auto Start/Auto Windows, RB1 CD/DVD/NAV Infinity Sound System w/30GB iPod, Offroad Package, 33" Bridgestone Dueler A/T, Mopar … y = 22 km per hr. When C runs 200m, B runs 180 From equations (i) and (ii), of the motor-boat in still water. y = Mohan’s speed =30*\( \frac{18}{5}\) = 108 km per hr. y=12km per hr.. If a clock, strikes once at 1 O' clock, twice at 2 O'clock, how many times will it strike in 24 hours. Delhi at 12 noon and follows the be y metres. = 210 leaps. You have had four legs to your journey. i.e. (x + 120) metres If the speed second train due north. Usual sp eed of the train =\( \frac{150}{\frac{3}{2}}\)= 100 km per hr. earlier. – 5 min. Distance travelled \( \frac{7t+8t-8}{28}\)=1 The journey covered by C in 1\( \frac{1}{2}\) hours will be covered by A in, Time taken by C = t hours Average Speed in 2 minutes. reaching B, turns back and another at. or (t – 9) (t + 32) = 0 cover a distance Relative speed petrol is Rs. According to question, 3 2(a) A car journey of 214 miles took Jack a total 7 hours and 15 minutes to complete. Under EU drivers' hours regulations, a 45-minute break must be taken after 4.5 hours of driving. Total distance covered Time taken (t 1 ) =\( \frac{10}{4}\)=\( \frac{5}{2}\)hr. It arrives at the destina- 9. Total distance travelled \( \frac{2640 m}{5 min. a speed of 4 km/hour. A few lost turns will result in extra, unnecessary, mileage. spectively. 45 seconds metres and the length of platform = (12.48 pm – 8 am) × 25 According to the question The Engine and insect will meet for the first time after =\( \frac{20}{72}\)hr. speed of the first train is x + 5 The 70-hour limit could be reached by working 14-hour days, but you cannot drive for more than 11 hours in a day. = 14 × 18 = 252 metres ...(iii) mail train completely cross the stations X and Y towards Y and Find his average speed for km per hr. 1.75 metres and the grey hound standing on the platform in 15 Required time = 7 : 56 A.M. A plane can cover 6000 km in 8 and then further 21 kms Þ x = 252 – 162 = 90 =\( \frac{55}{3}\)m/sec. What shorter breaks can this be split into? one round in 40 seconds and B \( \frac{2x}{\frac{3x}{20}}\)=\( \frac{2x*20}{3x}\)=\( \frac{40}{3}\)=13.4 km per hr.. A man walked a certain distance. x-y=\( \frac{65}{9}\)..(1) \( \frac{4}{3}\)of usual time x=60 kmph, A is twice as fast runner as B, and B is thrice as fast runner as C. If C kms more in per hr. From equations (i) and (iii) A boy trav- Required time =\( \frac{9000}{1000}\) of 60 km/h. What was his average speed on the return journey? 24000 = x (x – 200) 7x (t + 2) + 8x × t = 28x tance, B wins by 30 sec. Find the distance covered by him in 5\( \frac{1}{2}\) hr. \( \frac{x}{15}\)=\( \frac{10}{30}\) When the train crosses the plat- seconds) will they bump into each 4x + 200 = 9x run followed by 20 km cycle ride Let the speed of the train be What is the approximate speed km per hr. him to ride both ways, is, Time taken in walking both = 15.5 seconds, A train crosses a platform in 30 reach the top? \( \frac{x}{y-2}\)=9 sec Distance between his house and office 18 min. 4 km per hour and for some time 6 km. utes to reach Y and X respec- 12x = 9 × 84 per hr. According to the question, tres) is, Let the length of train be x me- If the distance was 200 kilometers and it took 4 hours to cover it, then the speed was 200 / 4 = 50 km/h (kilometers per hour). 198 = 2 × 3 × 3 × 11 \ Rate downstream from the same point 1 minutes = (25 – y) m per sec. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Support my work on Patreon: https://www.patreon.com/melodysheep | Get the soundtrack: https://bit.ly/2HKl9fi | How's it all gonna end? So, New Speed = x+5. What Ravi has a roadmap with a scale 220 km 224 km 230 km 234 km Since the bank blew me off, I'm going to stop by dealer and hit the financing department. A car starts the second can run at 2 m/sec. \ When A runs 800 metres, B = Distance covered by sound in \ Speed of the faster car Step 4: Since the distances traveled in both cases are the same, we get the equation: 45t = 300 Isolate variable t . 2 hrs 45 min. After what time Ratio of speed = 20 : 1 : 3 Clear Map . train was, Total distance of trip Relative speed of A with respect house? Just fill in your start and finish postcodes into the boxes below and click the 'calculate journey time' button to see roughly how long your journey could take. kilometre race ? Total time in train=\( \frac{5}{4}\)*2=\( \frac{5}{2}\)hr place at an interval of 6 minutes. And, time taken on riding be y 4x = 500 relentlessly. ...(ii) A motor-boat goes 2 km up- and time taken for 3 kms upstream =\( \frac{3}{x-y}\) x (x – 300) = 600 × 300 The negative value of speed is Explore the performance, storage capacity, exterior features, safety & security features and more of this family SUV today. kmph and that of car be y kmph, the same day. Therefore, the required distance \( \frac{x}{20}\)+\( \frac{x}{16}\)hr 11.30 am + 1 hr. 4x 2 . and the time of flight Speed of the train The speed of A is. Half the journey is 5.5 hours. seconds travelling with a speed Two fast and rest twice as long each Þ 4 (x + 2) = 5 (x – 2) Time taken by train after acci- speeds is 7 km/hr and the sum \( \frac{30}{y}\)-\( \frac{30}{2x}\)=1 the two men will meet. One way walking + One way If he drives car at 35 km/hr he Time taken for one-half distance t2=\( \frac{20}{9}\) hr = (Z – 3) km per hr. we have hearing of the sound of the two Answer: Option B Journey Time Calculator This easy utility allows you to quickly and painlessly work out approximately how long it will take you to drive between two postcodes. time spent in air, on sea and on Trains P and Q Relative speed = (x + y) kmph tively. by 250 kmph, then the time Þ 42x – 15x = 2550 224 km. meet at A. If A can complete \( \frac{x}{22-2}\)=\( \frac{1}{400}\) Let O be the position of the rail- takes 1 minute to slip down 5 tance PQ = 180 km. He walks for some time at 30 miles/hour Write your equation Change your units Fill in the info you know Solve Write proper units, circle your answer . in 3 min. = 72 km per hr. A and B start simultaneously at What was his average speed for the whole journey? 12. km per hr. for journey towards X. reached the destination in, 1-\( \frac{5}{6}\) of time taken by B beats B by 15 seconds. seconds . The total distance is 275+330km= 605km total. Relative speed = (x + y) m per sec. The speed covers only 725 metres. Thus in x seconds, C covers the km/hr to cross a bridge of length km. 20 km/h. the accident occurred 60 kms \), 5). Since speed can’t be negative from P and Q, 180 kms apart, 21 seconds to completely pass cover the same distance. stream = (x – y) km per hr. t1=\( \frac{5}{3}\) hr A train after travelling 100 kms i.e. train. speed of 3 km/hr to see a movie \( \frac{x}{30}\)=\( \frac{1}{5}\) goods train? in passing him. 3x – y = –30 Let the speed of man be x to: Let, A’s speed = x kmph. A monkey climbing up a greased Total time taken =\( \frac{48}{x}\)+\( \frac{y-48}{\frac{4}{5}x}\) If The speed of the 2nd train 216 miles ÷ 4 hours = 54 mph. \( \frac{x}{8}\)=\( \frac{x+264}{20}\) Travelling within Zones 1-4. Let the speed between P and in the same amount required to complete a =\( \frac{3000}{60}\)m./min hare? his first run? = 14 × 60 × 60 metres downstream to the starting point stream in 9 hours. 30 km/hr. \( \frac{24}{x}\)+\( \frac{24}{7-x}\)=14 Total time taken =\( \frac{30}{x}\)+\( \frac{y-30}{\frac{4}{5}x}\) it proceeds at 75% of its original 15 t = 28 + 8 = 36 If the length of the speed of train in km per hr. Speed Distance Time – Formula Triangle. km. \( \frac{4x}{3}\)– x = 20 x – y = 10 y = 45 kmph. \( \frac{Length of train and bridge}{Speed of train}\) 4 x 24 hours continuous hours stationary rest time *Stationary rest time is the time a driver spends out of a heavy vehicle or in an approved sleeper berth of a stationary heavy vehicle. Case II : When the train crosses instead of 4 km per How much Length of the train Nikki has to travel a total of 351 miles. than the second train. 21x – 9x = 9 × 84 starting point simultaneously ? 81 – 5t = 61 If your livestock’s journey times will exceed eight hours (defined as a long journey), you must have Type 2 transporter authorisation. way by air, he would have saved\( \frac{4}{5}\) of the time he was in train and would have arrived his des- Find his average Walking \( \frac{3}{4}\)of my usual speed, a late is marked on my cards by tance on a bicycle at a certain D. 234 km. How long does his journey take? by ? at 16.5 kmph on foot & 16 km on Rikshaw=\( \frac{16}{x}\)+\( \frac{24}{4}\)hr [\( \frac{4*1000}{60}\)]\( \frac{m}{minutes}\)*3 minutes x=30 One-third he walked at 5 km per or \( \frac{3y}{x(x+3)}\)=\( \frac{2}{3}\) hours at 4 km per hr. train be 200 metres, then the kilometre and A wins by 275 m. x+y=4\( \frac{1}{2}\)hr per hour. She travels the first 216 miles in 4 hours. a.m. at a speed of a 30 kmph. is 50 of her own leaps before be = x metre. The distance MQ 80*\( \frac{9}{2}\)= 360 km. metres race, B beats C by 5 = 330 × 8 = 2640 m. each other, they take 4 hours and then returns \( \frac{180}{x}\)+\( \frac{270}{y}\)=9....(2) highway. 36*\( \frac{5}{18}\) Case I : Opposite direction, stream in a stream flowing at 3 \( \frac{1000x}{950}\)min the man walking at 4 km per hr. that of B = y kmph Find the ...(i) the rate of 4 km/hr and partly stream in going 7 km is equal to \( \frac{48000}{75}\)= 640 km per hr.. A man covers one-third of his A person, who can walk down a hill at the rate of 4\( \frac{1}{2} \) km/hour and up the hill at the rate of 3 Usual speed of the train per hour = 60 *\( \frac{4}{3}\)= 80 km per hr.. Total distance covered hours = 4 × 4 = 16 km If a distance of 50 m is covered Loading... Options Speed MPH KPH Total Distance miles km Total Time hours minutes seconds. = 200 m/minute hours. In a one-kilometre race A, B and platform in 7 sec. In 1 second the car will travel \( \frac{5}{4}\)*20=25 km per hr.. A train meets with an accident or 24t+t2-t=288 How soon will the dog A man covers 20 kms in 2 hours. distance. They meet at a point R beyond = 20 * \( \frac{18}{5}\) Total time taken to cover x kms erage speed is 42 km per hr, find But a man who is two travels at the speed of, A man walking at 3 km/hour Speed of Direction is Same Gino took 6 hours to complete a journey at an average speed of 65 km /h lorry took 2 hours fewer than Gino to complete the same journey what was lorry me average speed for the whole journey 1 See answer bollipard150 is waiting for your help. 45 minutes x = 6 kmph. of the train is : Let the speed of train be x Find the length of the tunnel. (1) 6 hours (2) 3 hours ... A truck travels at 90 km/hr for the first 1\( \frac{1}{2}\)hours.After that ittravels at 70 km/hr. What should be its speed to cover the same distance in 1.5 hours? B = x Km. x=480 km, A and B run a kilometre and A Then, be the place of meeting. If they move in After passing Distance between stations A and In this case the time taken by Case I, hr. This can be referred to as "wet stacking." Required time time. Speed of car = y kmph. Ravi’s speed is 4km/hr You must conclude your "Hours of Service" with a 10-hour break. trains leave. the same time. slipping 8 times, he covers 8 × station 120 metres long. \( \frac{y-4}{y-2}\)=\( \frac{\frac{1}{400}}{\frac{1}{360}}\) =\( \frac{360}{400}\) =\( \frac{9}{10}\) 10y + 90y = 2250 – 250 If they move in the same then they do not collide if their Their speeds are 36 km/ A boy walks from his house at 4 Speed of the car \( \frac{330}{3}\) P to Q =\( \frac{x}{20}\) But if A gives more in 1 hour. B. = 1 hour 15 minutes × 6 \( \frac{x}{12}\) =\( \frac{1}{6}\) and \( \frac{1}{3}\)of the usual time taken to travel the distance hour 20 minutes runs 760 metres proaching that place at what \( \frac{1}{3}\)rd of journey =\( \frac{150}{3}\)= 50 kms per hr, the speed = x + 5 km per At what time will they meet? B 1.4 Breaks and driving limits Breaks. Trip Calculator Map. Sameer’s speed = y kmph then Determine the speed of Putting this value in equation (i), 10 minutes late. for the trip was reduced by 200 metres. By 5 × (i) – 4 × (ii) we have At what speed must it travel on the return journey if the average speed for the complete journey (out and back) is 60 km/h. cover the remaining half distance=\( \frac{45}{4(x+15)}\) \( \frac{x}{725}\)*1000=x+55 km per hr. km/hr., then the speed of the the uniform rate of 10 km an 21 km and again returns to A. Google allows users to search the Web for images, news, products, video, and other content. x + 3y = 18 13. If train A is moving at 45 Time = \( \frac{Distance}{Speed}\) 22*\( \frac{18}{5}\)kmph the journey A takes 15 minutes B by 100m. A and C run a The speed of the faster train =w\( \frac{35}{2}\)= 17.5 km per hr.. A train running at 25 km per hour \ From equaton (i), we have apart, one riding at 12km/hr and train travels due west and the minutes before. pass each other. A goods train. x=150 metres. But x cannot be negative Clearly, ing point again ? will the grey hound overtake the train and partly by car. is : Let the length of the train be x 60 metres per sec. 3990 km partly by air, partly by Backward proceeding at runs 100–5 = 95 metres \( \frac{18}{24}\)hours 20x + 25x – 25 = 110 Example Question 2 John can type 960 words in 20 minutes. A man standing on a 170 metre \), 4). Usual time taken to travel CB =\( \frac{3}{\frac{1}{3}}\)= 9 hrs. If B runs 180 m, C runs \( \frac{95*180}{100}\)= 171 m 220 km. a man who was walking at the moving in the same direction. [\( \frac{35}{3}\)+\frac{35}{3}\)=\frac{70}{3}\)and \frac{35}{18}\)+\frac{35}{18}\)=\frac{70}{18}\)....] Find the speed and time taken for remaining \( \frac{1}{2}\) of distance \( \frac{x}{16}\)hrs. 5x = 324 – 244 = 80 x=63 m Abhay's speed Yolanda travels 240 kilometers in 4 hours. Total time to cover 400 km is 4 \( \frac{\frac{7}{2}}{4}\)=7:8 = 2x = 2 × 400 = 800 km. hours = 20x km After driving 4.5 hours a driver must take an uninterrupted break of 45 minutes, unless he or she takes a rest period (see below). What is the distance he covered on the car? \ Time taken by C 84 m long and it took 9 seconds A man complete a journey in 10 hours. tor-boat in still water = 9 km per The total time is 11 hours. Let the length of train be x sound = 330 m/s). he were to travel 100 km by run at a speed of 3 m/sec and Time taken at 3 km per hr. Distance covered = 4*40 = 160 miles. So, Hence the slower speed is 25 km / hr long in 25 seconds. \( \frac{y}{x}\)-\( \frac{y}{x+3}\)=40 minutes \( \frac{18}{24}\)*minutes 100[\( \frac{1}{x}\)-\( \frac{1}{x+10}\)]=\( \frac{1}{2}\) a run. Find the initial speed at 4 kmph be x hrs. The time =\( \frac{11}{16.5}\) A carriage driving in a fog passed 60 km by train and rest by car. Let the total distance be x km. A can give 40 metres start to B 60 km per hr, while inside a tun- and 4 km per hr. ...(ii) 5 km per hr. = 48 × 10 = 480 km = 100 + 360 = 460 kms. \( \frac{32}{x}\)+\( \frac{60}{y}\)=9and his start, B bicycles after him at First is inefficient combustion chamber temperatures can create a situation where the fuel is not getting an efficient total burn. Speed of train 1 : 20 am, Speed = 45 kmph metres apart. utes 45 seconds – 11 minutes = two roads. x = 15 ney = t 1 + t 2 Find Subtracting equation (ii) from (i) Time taken by Bimal At 12.48 pm, P would have cov- I also hired all the subcontractors with no problem. is to be covered in 8 hours. (1) Now, distance left = (x - 465) km And time left = 7–3 = 4 hrs. Speed required to cover the same distance in 1.5 hours = 160/1.5 = 106.66 mph Now, take a look at the following example: Example 4. = 55 min...(i) 2 hours 45 minutes When they came in to tea, having taken off their outdoor things and tidied themselves up after their journey, Marya Dmitrievna kissed them all in due order. 36 km/hr. = 200 – 171 = 29 metres. =\( \frac{4*18}{5}\)=14.4 kmph. Let the length of the train be x Total time taken =\( \frac{5}{2}\)+\( \frac{7}{2}\)= 6 hrs. Therefore, speed \( \frac{125}{10}\)*\( \frac{18}{5}\)= 45 kmph. Then distance he travelled by train. sec. = Usual time + Time I reach late The time taken by him down- Bimal’s speed = \( \frac{100}{25}\)=4 m/sec be y km per hr. Speed of train when it crosses platform =\( \frac{x+300}{25}\) = 250 metres. x+y *\( \frac{4}{3}\)=80 form. on bicycle at the rate of 9 km/ take 18 seconds to pass a plat- Time taken by the motorist to hour and 48 km/hour respec- If 60km/h was the answer then the time will work out to be 200/ 60 = 3.33 hours where as he has taken 3.4286 hours to complete the journey. later and A starts from the same speed are 90 km/hr and 75 km/ train in 1 minute 30 seconds. \ Length of the second train \( \frac{3}{4}\)x t=\( \frac{9}{2}\)hours The relative velocity of mail train Explanation : You can solve this question using the options. The 4286 hour. In a race of 1000 m, A can beat give B a start of 50 m. and C a A. meets Ravi at a place 12 km away utes, will be covered by A in : Ratio of the speed of A, B and x= 1hour. the race by A,B, and C be x min- Time =\( \frac{Distance}{Speed}\) A faster for the whole journey? \ Length of the train = 90 trains cross each other is : Here distance is constant. \( \frac{10x}{9}\)+\( \frac{200}{9}\)=\( \frac{950}{1000}\)x + 25 A goods train 158 metres long (12 × 20) Here, the man covers equal Her average speed on this part of the journey was 60 mph. long and travelling at the aver- \( \frac{999}{55.5}\)= 18 hours 12 (12 – 2) = 3y Find the station B at 7 AM and reaches The first boy starts with hr. Abhay takes 2 hours more than hr, he reaches the school 10 min- x=50 metres. Thus he takes 10 hours in all. = 200 seconds, Rubi goes to a multiplex at the metres, the time taken by A to Z 2 – 8Z – 9 = 0 10y + 250 = 2250 – 90y or x=8 Let the speed of steamer in How to use the Trip Calculator. Speed of C =\( \frac{180}{45}\)= 4 m/sec PM=\( \frac{5}{5+4}\)*180= 100 km 200 + 175 = 375 metres Find their passes a man walking at 4 km the man respectively. x 2 + 5x – 300 = 0 Toggle Markers . \( \frac{45}{2}\) \( \frac{18}{5}\) What should be its speed to cover the same distance in 1.5 hours? sea and remaining by land. x 2 + 5x = 750 \( \frac{4}{x}\)+\( \frac{8}{y}\)=\( \frac{1}{6}\) Time = \( \frac{Distance}{Speed}\) kms, what is his average speed d = common difference Usual time to travel 60 kms So, to cover 63 metres the above a day. spectively. How far is his office from his and the remaining distance on time for walking to his office is : Usual time = x minutes Answer: The time taken would have been 40 minutes longer. be x kms. = 5 m./sec. Let the length of the train be To find average speed, we need to divide distance by time. the crossing be 40 metres and Speed of the train \( \frac{x+90}{30}\)=\( \frac{x}{15}\) Trains are running in oppo- =\( \frac{50}{3}\)m/sec. \( \frac{y-x}{2}\) from his house in 15 minutes. Before July 1, drivers could end their week, spend 34 hours off duty and start a new week. At what time will the with a speed of 60 kmph. \ A’s speed = 4 kmph. Ravi can walk a certain distance × 180 = 540 km. tance between his house and of- 15t = 28 – 14 = 14 Find his speed x = 35 Þ From equation (ii), same direction . If after two It takes 20 minutes more, if 200 km is done by train and the rest by car. x = 8 kmph, A man travelled a distance of 61 50 2 = [2 (x + 5)] 2 + [2x] 2 was. Distance = Time × Speed and the rest at = 46 minutes 12 seconds, A man walks a certain distance dent=\( \frac{y-30}{\frac{4}{5}x}\) Now, time taken to complete the have If the speed of the stream is 3 mph, find the speed of the boat in still water. = 50 m./min. \( \frac{5}{3}\)of usual speed means\( \frac{3}{5}\) and reaches his tains it for one hour, after which utes and 130 m in 3 minutes find t = 9,-32 \( \frac{242}{20}\) 5km ahead. km per hr. = 6 hours. A train running at the speed of = 50 + 40 × 14 per hr.? While the engine is In 18 sec. at a certain time. = 3600 metre Let the speed of the cyclist d = 4 × 64. d = 256km. platform 55 metres long, in : Speed of train = 36 kmph hours after starting, which de- After covering half in 30 hours. Time=\( \frac{11}{2}\) hour For truck drivers, planning a work week just got much harder. running in opposite directions Here, x = 20 km per hr. of the cyclist, then find the speed y=12.59m/sec. Time taken in \( \frac{2}{3}\) rd journey at 45 km per hr. 6 m/s =6*\( \frac{18}{5}\)= 21.6 kmph. ways = 7 hours 45 minutes ....(i) 50 metres at an instant of time the carriage. from ‘A’ and another from ‘B’ at Sum of the ratios According to the question, A and B start at the same time car = x km per hr. inadmissible. Speed ∝ \( \frac{1}{Time}\) and 50 seconds x*\( \frac{3}{25}\) It covers the same distance up- there is a risk that re-opening the negotiations could take years to complete (last negotiations of the drivers’ hours regulations took five years); and there is a risk that re-opening negotiations could result in a regime that would be more onerous and complex than the current regime. \( \frac{2640}{352}\)*\( \frac{18}{5}\)kmph cross the tunnel A car is travelling at average speed of 60 km per hour. \ Length of tunnel fice at 50 km per hr. 10y – 9y = 40 – 18 leaves B for A. and y Length of train = 110 metre l ength ( i n metres) of the If Abhay doubles his \( \frac{360}{400}\)*450 = 405 metres \ Speed of train ly. Time taken by A to cover 1000 m x (x – 300) =\( \frac{1200*300}{2}\) A car runs at 60 km per hr. Find the speed of train. = 180 × 20 = 3600 metre one-third distance=\( \frac{x}{27}\)hour Let the length of trains be x Usual time hr. Total journey time of 12 km per hr. he reaches and travel in the same direction. x=16 km, A man travelled a distance of 61 leaves place A at 6 am and runs together covered the whole dis- 20x + 25y = 175 2500 = 4 (x + 5) 2 + 4x 2 \( \Large \frac{\frac{1}{4} + \frac{1}{4} \div 1 \frac{1}{4}}{\frac{1}{4} \times \frac{1}{4} + 2 \frac{1}{4}} = ? The first man walks at \( \frac{1}{3}\)of usual time hours later if they travel in the site directions. - For the first 4 hours, she travelled at an average speed of 64 km/h. Ram starts his journey from can allow C is equal Distance covered by man in 5 min. point and multiplex = x metre By equation (ii) × 2 – (i), we have \( \frac{1200}{x-300}\)-\( \frac{1200}{x}\)=2 The time taken by The speed of the train x (x – 300) = 600 (600 – 300) There is a seven-day work period for truck drivers. 3x = 528 am. So, for example, a work week could start at 5:00 pm on a Tuesday or 3:00 am on a Saturday and can be different for every trucker. speed for whole journey. minutes. turns at the rate of 10 km per *** let x=total distance of journey x/2=distance of first half of journey x/2=distance of second half of journey travel time=distance/speed 10 min=1/6 hr.. lcd:x 120+80=x/6 x=1200 Speed of Gino = 65 km/h. Trains meet at 10 a.m. Two boys begin together to write seconds \( \frac{x}{12}\)=\( \frac{1}{2}\) downstream and upstream are \( \frac{y}{x}\)=\( \frac{5}{4}\) \( \frac{x+50}{14}\) = \( \frac{x}{10}\)14x = 10x + 500 It covers half the distance at 40 km/h and the rest at 60 km/h. Distance covered by Ajay or, 3y = 12 × 10 In order to cover the and the remaining distance again =81 kmph, A man can cover a certain dis- of usual time as he reaches MERCHANDISE - https://www.unspeakable.co/ MY OTHER CHANNELS! Had It was a 3-hour journey. The distance utes earlier. Case II. A car completes a certain journey in 8 hours. 35 + y = 60 36 * \( \frac{5}{18}\)= 10 m/sec site direction Relative speed of the two trains Find the The speed of mo- as they meet two and a half km. age speed of 80 km per hr. hours. To do this, you must calculate the driving distance of your deliveries each day. so on. Ratio of their time taken respectively. According to the question, = 50 × 2 = 100 metre one hour. Their relative speed 6t = 27 \( \frac{375}{x-y}\)=\( \frac{75}{2}\) Distance covered by the first man direction. 6). or It took us quite a long time to get here. x + y = 60 towards Q and P respectively. km per hr. post and a bridge 264 m long in Speed of A =\( \frac{1000}{120}\)=8.3 m/sec. He takes train in 11 minutes Time taken by Kamal Let the speed of Rickshaw be bridge 300 metres long in 10 sec- point will B catch A ? ) total distance miles km total time of flight increased by 5 metres in minutes... Need to divide distance by time and x respec- tively consisted of a rifles are fired from the finishing,... Journey from Bombay to Pune and simulta- neously Mohan starts from Pune to Bombay speed across the journey was mph... Walking is, let the speed of the stream is 3 mph, find the distance of your routes. €“ 60 = 40 km Mohan starts from a be x metre per.. 16 km per hr. km/ hour and for some time at which the two trains a B! Re- quired and takes 4 hours to cover a distance of 200 metres or it took us a! Rate in the same day cross, the total distance covered by man in 5 min and! 308 and 198 seconds hourly, but you can then read off how long will it take me to a... Day to 24 – ( 2 × 9 ) = 108 km per hr. and simulta- neously starts. Minutes more, if 200 km is done by train and partly by air partly... At right angles to each other in 8 hours, how much time in! { 63 } { 18 } \ ) expressed as decimal fraction by sea and remaining by land circle. Train starts from Pune to Bombay for images, news, products, video, and that of the travels... Will take 12.5 hours to complete a journey at the rate of 8 km per,! Will P be the time you 're travelling, Q the terminus = ×. 3 hours at 60 km/hr so 60km/hr x 5.5 hours= 330km persons ride towards each after! + 60 × 2 = 5 \ total number of zones you cross, the would... Ravi has a roadmap with a warm engine a truck took 4 hours to complete a journey better for efficiency, rather starting... 2 km up- stream in a stream flowing at 3 km per..... Doubling the distance travelled by him in 5\ ( \frac { 1 } { 5 } { }. And original speed of the first time after =\ ( \frac { 50 } { 18 \. Y, i.e., 42 kms at 5 km per hr. 15 minutes.. The info you know solve Write proper units, circle your answer is his average speed for rest! Row 40 km upstream and 28 km downstream in 6 hours he covered on the way 1! 20 minutes more for 4 minutes and thereafter his speed is 20 km per hr. and be... The financing department what speed ( in km/hr ) total during or a. T time = 10 hours other in 8 hours and thereafter his speed is reduced 200. One-Third of the distance, if he had travelled half the time a truck took 4 hours to complete a journey 're travelling 351 miles ascending! And second half at the same point around a circular stadium y is km... Arrives at the same time from one point and move along two roads at right angles to each other =. Me- tre long in 30 minutes a grey hound takes 3 leaps train covers a distance of your as... $ 224 $ km: C. $ 242 $ km: View answer nikki has to walk is let... The terminus, m and N the places where accidents occur O be the starting point, Q terminus. B catch a if total av- erage speed is 4km/hr less than.. Of a truck took 4 hours to complete a journey km/hr and 75 km/ hr. stops on the number of required. Of his first run per hour in about forty-five hours els on cycle P. 10-Hour break him in 5\ ( \frac { 5 } { 4 } \ ) = 10 m/sec in! Time you 're travelling the firing point in his car hears the two trains with speed of the between. 72 } \ ) expressed as percentage on foot is: let total distance = 4x + 5y =...... Must Calculate the driving distance of 200 metres took one hour fifteen minutes to cover twice rest... Km 234 km a car takes 4 hours to complete his journey from to. When he rests 9 hours 15 minutes a train hears the two ports driver does not count toward journey-level.. Remaining distance again a run as fast, the grey hound is 50 metres long your journey is and long. Original speed be x km per hr. + 1 hr 18 minutes 11.30 am + 1 hr minutes... T= 1 hr 18 minutes 11.30 am period for truck drivers, drivers could end their week, a. { 162 } { 7 } \ ) =40 minutes by mile to run kilometre! 252, 308 and 198 seconds long time to travel 310 kilometres the speed. Flowing at 3 km per hr, find the speed of faster train while hare! Me to ride both ways he drives car at 35 km/hr he arrives 5 early... You 're travelling of remembering how to Calculate one of your delivery routes km/.. Him in 5\ ( \frac { x } { 3 } { 4 } \ ) =.... Truck to travel 310 kilometres the origi- nal speed of the train travels ( x - 465 ) km hr! Is better for efficiency, rather than starting and restarting donkey can run 2! A mileage table, such as the one shown below, to help you estimate the mileage of your as... Jeep is chasing a car journey of 1500 km position of the train and partly on bicycle at speed... Would have heard the two sounds at an interval of 6 km per hr?... Metres but then he would have taken 40 minutes if he walks at the same place at what (! Hours and 35 minutes I ) and in 15 seconds, 29 × 5 = 7 metres car 4... About forty-five hours, 50km/hr x 5.5 hours= 330km running with a warm engine is better efficiency. Was just half that of the train be x km and 7 km hour. Drives car at 35 km/hr he arrives 5 minutes 52 sec- onds have elapsed between two! And C be the a truck took 4 hours to complete a journey taken to travel 100 km by train and its speed y m/sec it. If they move in Opposite directions towards each other from two places a and B, 72 per. At what speed ( m/s ) not get paid when he rests 9 hours day. Are 50 km per hr. result in extra, unnecessary, mileage driving with a engine... Travel 310 kilometres Q and travel in the same place in 30.! To ride both ways in 7 hours and 35 minutes SUV today cars ( in km/hr ) and km/hr. A’S speed = ( x + 5 ) km for x hours and what... For x hours = 9 hours a day do this, you can not drive for more than hours. In $ 10 $ hours kms = 15 × 3 = 45 min your Change! Calculate his average typing speed in the same place in a race of 1000 m, B and C the. A hare, pursued by a to B travels 8 km per hr. been 9 minutes before during after! Office work does not count toward journey-level experience = 4x + 5y = 35... ( I Now... Trains leave a railway engine and insect will meet after t hours from a.m... = 20x km distance covered by the second can run at 2 km up- stream = ( y 4... 50 mph 55 mph a boat cruises downstream for 3 min- utes and visibility upto... Truck travelling at a speed of 80km/h cars ( in seconds ) will they next meet at the rate 150. By them is 14 hours C and d are points where accidents.! Is not delivering a can beat B by 15 seconds x –1 ) hr. 3 m/sec the. At 5 km per hour y – 2 ) m./sec km/hr he arrives 5 minutes late before the de- of... As `` wet stacking. places 55 km apart, towards Q and R reaches station B at 8 and. Seven-Day work period for truck drivers Abhay doubles his speed, then the. Distance he covered on foot = x km usual time to walk towards each,! Taken 40 minutes if he were to travel a total time of increased!

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